Physics, 09.03.2020 18:51 junkmailemail42
An electron with kinetic energy 2.80 eV encounters a potential barrier of height 4.70 eV. If the barrier width is 0.40 nm, what is the probability that the electron will tunnel through the barrier? (1 eV = 1.60 × 10-19 J, m el = 9.11 × 10-31 kg, ℏℏ = 1.055 × 10-34 J · s, h = 6.626 × 10-34 J · s) An electron with kinetic energy 2.80 eV encounters a potential barrier of height 4.70 eV. If the barrier width is 0.40 nm, what is the probability that the electron will tunnel through the barrier? (1 eV = 1.60 × 10-19 J, m el = 9.11 × 10-31 kg, = 1.055 × 10-34 J · s, h = 6.626 × 10-34 J · s) 3.5 × 10-3 7.3 × 10-3 1.4 × 10-2 3.5 × 10-2 2.9 × 10-3
Answers: 1
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An electron with kinetic energy 2.80 eV encounters a potential barrier of height 4.70 eV. If the bar...
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