Water vapor enters a turbine operating at steady state at 500°C, 40 bar, with a velocity of 200 m/s, and expands adiabatically to the exit, where it is saturated vapor at 0.8 bar, with a velocity of 150 m/s and a volumetric flow rate of 20 m3 /s. Determine the power developed by the turbine, in kW.

The power developed by the turbine is 7553.8 kW

Explanation:

First we determine the mass flow rate of steam.

given volumetric flow rate as 20 m³ /s

from steam table, density of steam at 0.8 bar = 2.087 kg/m³

Based on energy equation and considering adiabatic flow;

given;

V₁ = 200 m/s,  V₂ = 150 m/s

from steam table, at saturated vapor pressure of 0.8 bar, h₂ = 2665.8 kJ/kg, also at vapor pressure of 40 bar and 500°C, h₁ = 3445.3 kJ/kg

Therefore, the power developed by the turbine is 7553.8 kW

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~