Physics, 09.03.2020 21:53 olamagdziak2007
Two spheres of mass M1 and M2 are arranged one above the other as shown. They are separated by a fraction of a mm. They are released from rest and allowed to fall to the ground, a distance h = 7.0 m below. Mass M2 collides elastically with the ground and then elastically with mass M1. Calculate the maximum height the center of M1 rises above the ground after the collision. D = 20 cm, d = 5 cm, M1 = 0.14 kg, M2 = 1.10 kg.
Answers: 3
Physics, 22.06.2019 20:40
Abasketball star covers 2.65 m horizontally in a jump to dunk the ball. his motion through space can be modeled precisely as that of a particle at his center of mass. his center of mass is at elevation 1.02 m when he leaves the floor. it reaches a maximum height of 1.90 m above the floor and is at elevation 0.910 m when he touches down again. (a) determine his time of flight (his "hang time"). (b) determine his horizontal velocity at the instant of takeoff. (c) determine his vertical velocity at the instant of takeoff. (d) determine his takeoff angle. (e) for comparison, determine the hang time of a whitetail deer making a jump with center-of-mass elevations yi = 1.20 m, ymax = 2.45 m, and yf = 0.750 m.
Answers: 1
Physics, 22.06.2019 21:00
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Answers: 1
Two spheres of mass M1 and M2 are arranged one above the other as shown. They are separated by a fra...
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