The friends consider a block of mass 1.1 kg set in motion by an external force. The initial velocity is 1.6 m/s, and the coefficient of kinetic friction is 0.03. What do they find as the final change in internal energy of the system once the block comes to a complete stop

Explanation:

The given data is as follows.

         Final K.E = 0,    

and,    Initial K.E =

So, we will calculate the initial kinetic energy as follows.

         Initial K.E =      

                       =

                       = 1.408 J

Now, we will calculate the change in kinetic energy as follows.

        = Final K.E - Initial K.E

                      = 0 - 1.408 J

Thus, we can conclude that the change in kinetic energy is 1.408 J.

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz