A stationary detector measures the frequency of a sound source that first moves at constant velocity directly toward the detector and then (after passing the detector) directly away from it. The emitted frequency is f. During the approach the detected frequency is f app and during the recession it is f rec. If ( f app f rec)/f 0.500, what is the ratio vs/v of the speed of the source to the speed of sound

the ratio of the speed of the source to the speed of sound = 2.47

Explanation: This question is solved by employing doppler effect formula.

The frequency of sound observed by the observer when the source of sound is moving toward him and the frequency of sound when it is moving away from him.

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When seismic waves hit a fault, the waves are reflected off the fault. seismograph can detect these reflected seismic waves. geologists then use these data to map the fault's length and depth

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.