The electron's velocity at that instant is purely horizontal with a magnitude of 2 \times 10^5 ~\text{m/s}2×10 5 m/s then how long will it take for the particle to pass through point (P) again?

Complete question:

At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10⁵ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.

[Assume that this experiment takes place in deep space so that the effect of gravity is negligible.]

The time it will take the particle to pass through point (P) again is 1.639 ns.

Explanation:

F = qvB

Also;

solving this two equations together;

where;

m is the mass of electron = 9.11 x 10⁻³¹ kg

q is the charge of electron = 1.602 x 10⁻¹⁹ C

B is the strength of the magnetic field = 3.47 x 10⁻³ T

substitute these values and solve for t

Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.

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