If the area of the plates of a parallel plate capacitor is halved, and the separation between the plates tripled, all while the charge on the capacitor remains constant, then by what factor does the electric field potential energy stored in the capacitor change?

Explanation:

The capacitance of a parallel plate capacitor is given by

where A is the area of plates and d is the separation between the plates.

Now the area is halved and the separation is tripled.

The new capacitance is

C' = C / 6

Initial potential energy is given by

here the charge is constant

The new energy is given by

U' = 6 U

The energy becomes six times the initial value.

spare some change and give it to the poor

explanation:

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the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.