Billiard ball A strikes another ball B of the same mass, which is at rest, such that after the impact they move at angles ΘA and ΘB respectively. The velocity of ball A after impact is 4.70 m/s at an angle ΘA = 33.0 ° while ball B moves with speed 4.50 m/s. Figure showing a layout of the problem as described in text What is ΘB (in degrees)? What is the original speed of ball A before impact?

7.6427m/s

Explanation:

Given:

#Applying the conservation of momentum along the x-axis:

#And along y-axis:

#Solving  for :

#By substitution in the x-axis equation:

Hence the original speed of the ball before impact is 7.6427m/s

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

the ima (higher than 1m) will be greater than the ima with the height of 1m.