Two equal forces are applied to a door. The first force is applied at the midpoint of the door; the second force is applied at the doorknob. Both forces are applied perpendicular to the door. Which force exerts the greater torque?A) the first at the midpointB) the second at the doorknobC) both exert equal non-zero torquesD) both exert zero torquesE) Additional information is needed.

The torque is more for the force applied at the doorknob.

The torque is defined as the force that allows for a rotation. A torque is measured by means of product between the force applied with the distance between the point of force application to the axis of the rotation of the body.

So in the first case, the torque is equal to the product of the force applied and the distance between the midpoint to the hinge of the door. In the second case, the torque is equal to force applied with the distance of doorknob from the hinge.

As the forces are equal, and the distance of the doorknob from the hinge is greater than that of midpoint, then the torque in the second case is more than that of 1st case.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2