Modulo 8 Channel and a Binary Source with Erasure Distortion
(35 points)
Consider the memoryless channel described by
Y = (X + Z) mod 8,
where the channel input X, output Y , and the noise Z are real valued. For example,
if x = 6.4 and z = 1.8 then y = 0.2. The noise is uniformly distributed on [−B, B],
i. e. Z ∼ Uniform[−B, B] and is independent of the input X. Assume that 0 < B ≤ 4
is a known channel parameter.
(a) Find the channel capacity as a function of B.
(b) A communication system is suggested where the permitted channel input values
are restricted to the set {1, 3, 5, 7}. Show that, when B = 1, it is still possible to
achieve the channel capacity. In fact, to achieve this capacity with zero probability
of error and with a very simple scheme.

4. 50x10= 500m/s 5. 52m/s

Nps pollution is caused by rainfall or snowmelt moving over and through the ground. nonpoint source pollution can include: excess fertilizers, herbicides and insecticides from agricultural lands and residential areas. oil, grease and toxic chemicals from urban runoff and energy production

So are u adding some additional catalyst

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)