An alpha particle travels at a velocity of magnitude 790 m/s through a uniform magnetic field of magnitude 0.047 T. (An alpha particle has a charge of charge of +3.2 × 10-19 C and a mass 6.6 × 10-27 kg) The angle between the particle's direction of motion and the magnetic field is 58°. What is the magnitude of

(a) the force acting on the particle due to the field, and

(b) the acceleration of the particle due to this force?

(c) Does the speed of the particle increase, decrease, or remain the same?

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )

iron would move it is magnetic there is a mag field around the current in the wire

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

statement #3 on andre"s list is false.