Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. Part A If the surface charge density for each plate has magnitude 47.0 nC/m2, what is the magnitude of E⃗ in the region between the plates?

5308.34 N/C

Explanation:

Given:

Surface density of each plate (σ) = 47.0 nC/m² =

Separation between the plates (d) = 2.20 cm

We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

Now, plug in   for 'σ' and for and solve for the electric field. This gives,

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C

there are no correct statementd on the list of choices you provided.

reserve is the answer