A toboggan having a mass of 10 kg starts from rest at A and carries a girl and boy having a mass of 40 kg and 45 kg, respectively. When the toboggan reaches the bottom of the slope at B, the boy is pushed off from the back with a horizontal velocity of vb>t = 2 m>s, measured relative to the toboggan. Determine the velocity of the toboggan afterwards. Neglect friction in the calculation.

The velocity of the toboggan is 7.51 m/s.

Explanation:

Given that,

Mass of toboggan = 10 kg

Mass of girl =40 kg

Mass of boy = 45 kg

Velocity = 2 m/s

Suppose that h = 3.2 m

We need to calculate the velocity

Using conservation of energy

Put the value into the formula

The velocity of boy is

We need to calculate the velocity of the toboggan

Using principle of momentum

Put the value into the formula

Hence, The velocity of the toboggan is 7.51 m/s.

like poles repel so keep pushing north to north and repels funny to see this

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation