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Physics, 12.03.2020 01:58 dabboy

To learn to apply the concept of current density and microscopic Ohm's law. A "gauge 8" jumper cable has a diameter ddd of 0.326 centimeters. The cable carries a current III of 30.0 amperes. The electric field EEE in the cable is 0.062 newtons per coulomb. Part APart complete Part B What electric field E′E′E' would have been required to create a current of 30.0 amperes in a copper "gauge 10" wire with diameter ddd equal to 0.259 centimeters?

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