An insulating spherical shell has an inner radius R1 and an outer radius R2. The shell has a uniform charge volume density of 10.0 nC/m3 and the electric field just outside the shell’s outer surface is radially directed and has a uniform strength of 120 N/C. A. If the shell’s outer radius is R2 = 1.1 m, what is its inner radius R1, in meters?

0.782m

Explanation:

Parameters given:

Volume charge density, ρ = 10 * 10^(-9) C/m³

Electric field outside the shell, E = 120 N/C

Outer radius, R2 = 1.1m

Inner radius, R1 =?

Volume charge density, ρ is given as:

ρ = Q/V

V = volume of shell = 4/3 * π * (R2 - R1)³

Therefore,

ρ = Q/[4/3 * π * (R2 - R1)³] (1)

The electric field outside the shell is given as:

E = kQ/(R2 - R1)² (2)

We can make charge, Q, the subject of the formula:

From (1):

Q = 4ρ/3 * π * (R2 - R1)³

From (2):

Q = E/k * (R2 - R1)²

Equating both formulae:

4ρ/3 * π * (R2 - R1)³ = E/k * (R2 - R1)²

=> (R2 - R1)³/(R2 - R1)² = 3E/(4πρk)

(R2 - R1) = 3E/(4πρk)

=> R1 = R2 - 3E/(4πρk)

Inserting the values of all parameters, k = Coulumbs constant:

R1 = 1.1 - (3 * 120)/(4 * π * 10 * 10^(-9) * 9 * 10^9)

R1 = 1.1 - 360/1131.12

R1 = 1.1 - 0.318

R1 = 0.782m

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.