An electric field of 1.65 kV/m and a magnetic field of 0.334 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?

4940.12 m/s

Explanation:

For the net force on the moving electron to be zero, the Magnetic force must then match the electric force.

Magnetic force = Electric force

Magnetic force = qvB

Electric force = Eq

qvB = Eq

v = (E/B)

E = Electric field = 1.65 kV/m = 1650 V/m

B = Magnetic field = 0.334 T

v = (1650/0.334)

v = 4940.12 m/s

Hope this helps!!

Explanation:

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