You observe someone pulling a block of mass 41 kg across a low-friction surface. While they pull a distance of 5 m in the direction of motion, the speed of the block changes from 5 m/s to 6 m/s. Calculate the magnitude of the force exerted by the person on the block.

45.1 N

Explanation:

Using Newton's Fundamental equation of Kinematics,

F = ma Equation 1

Where F = force exerted by the person on the block, m = mass of the block, a = acceleration of the block

We can look for the acceleration of the block by applying newton's equation of motion,

Using,

v² = u²+2as Equation 2

Where v = final velocity, u = initial velocity, a = acceleration, s = distance.

make a the subject of the equation

a = (v²-u²)/2s Equation 3

Given: v = 6 m/s, u = 5 m/s, s = 5 m

Substitute into equation 3

a = (6²-5²)/(2×5)

a = 11/10

a = 1.1 m/s²

Also Given: m = 41 kg

Substitute into equation 1

F = 41(1.1)

F = 45.1 N

where are the vectors ?

the force on the thing and the distance the force moves the thing