A m = 2.45 kg object hangs in equilibrium at the end of a rope (taken as massless) while a wind pushes the object with a F W = 18.9 N horizontal force. Find the magnitude of the tension in the rope and the rope's angle from the vertical. The acceleration due to gravity is g = 9.81 m/s2.

Tension on the rope = 30N

Angle from the vertical = 38.79°

Explanation:

The vertical force on the rope is given by :

F v= mg

Given: m = 2.45kg

Vertical force Fv = 2.45 × 9.8 = 23.52N

Tension on the rope, T = Sqrt( 18.9^2 + 23.52^2)

T = sqrt ( 357.21 + 553.19)

T = sqrt(910.4)

T = 30N

Vertical angle,theta = Tan^-1 (18.9/23.52)

Theta= Tan^-1(0.8036)

Theta= 38.79°

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

the inner core.

good luck: )

klicker