An electron moves with a speed of 5.0 × 104 m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the magnetic force on the electron? (e = 1.60 × 10-19 C) Group of answer choices

1.6×10⁻¹⁵ N

Explanation:

Using,

F = qvBsinФ Equation 1

Where F = Force, q = charge of the electron, v = speed of the electron, B =   Magnetic Field, Ф = angle between the magnetic Field and the electron speed.

Given: v = 5.0×10⁴, B = 0.2 T, q = 1.60×10⁻¹⁹ C, Ф = 90° ( Perpendicular)

F =  1.60×10⁻¹⁹ (5.0×10⁴)(0.2)sin90°

F = 1.6×10⁻¹⁵ N

Hence the magnitude of the magnetic force on the electron = 1.6×10⁻¹⁵ N

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