A 12.0-N object is oscillating in simple harmonic motion at the end of an ideal vertical spring. Its vertical position y as a function of time t is given by y(t)=4.50cmcos[(19.5s−1)t−π/8].(a) What is the spring constant of the spring?

465.6 N/m

Explanation:

We are given that

F=12 N

We have to find the spring constant of the spring.

Where

Using the formula

kg

Compare the given equation with

We get

Using the formula

Spring constant,

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.

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