A micromechanical resonator is vibrating at the frequency fo = 20 kHz with vibration aplitude x0 = 10 nm. The vibrations are measured using the rate-of-change measuremnent with a parallel plate capacitor that has the area A - 1000 um^2 and the gap d = 1um. Calculate the motional current if the bias voltage over the capacitor is Vdc = 5 V.

Motional current is -8.85 x 10 ^-6

Explanation:

As the data is given in the question :

     V = 5 V

     A = 1000  μm2

     f = 20 kHz

Amplitude = 10nm

As we know, the formula of the capacitance is :

C =q/v

C = ε0A /d

dc/dt = 1/V dq/dt

ε0A d/dt  (1/d) = 1/V i

-ε0A/d2 d(d)/dt = 1/V i

As we know,

            Amplitude = 10nm

            frequency = 20kHZ

            d(d) /dt = 10 x x 20 x

                         =0.2 x

          i = -ε0AV / x 0.2x

          i =

          i = -8.85 x

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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