An initially uncharged 3.67 μF capacitor and a 8.01 k Ω resistor are connected in series to a 1.50 V battery that has negligible internal resistance. What is the initial current in the circuit, expressed in milliamperes?

The initial current in the circuit is 0.1873 mA

Explanation:

Given;

capacitance is given as 3.67 x 10⁻⁶ F

resistance is given as 8010 Ω

voltage across the circuit is 1.5 V

Since the capacitor is initially uncharged, the capacitive reactance is zero.

From ohms law;

Voltage across the circuit is directly proportional to the opposition to the flow of current.

V = IR

I = V/R

I = 1.5/8010

I = 0.0001873 A = 0.1873 mA

Therefore, the initial current in the circuit is 0.1873 mA

it is the second option.

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