10.20) Perform the following conversions: (a) 0.912 atm to torr,(b) 0.685 bar to kilopascals, (c) 655 mm Hg to atmospheres,(d) 1.323 * 105 Pa to atmospheres, (e) 2.50 atm to psi. Perform the following conversions: (a) 0.912 atm to torr, (b) 0.685 bar to kilopascals, (c) 655 mm Hg to atmospheres, (d) 1.323 * 105 Pa to atmospheres, (e) 2.50 atm to psi.

(a)  0.912 atm = 693.12 torr

(b)  0.685 bar = 68.5 kpa

(c)  655 mm Hg = 0.8618 atm

(d)  1.323x10⁵ Pa = 1.305 atm

(e)  2.50 atm = 36.74 psi

Explanation:

(a) 0.912 atm to torr

We know that 1 atmospheric pressure (Atm) is equal to 760 torr (mm Hg)

so 0.912*760 = 693.12 torr

(b) 0.685 bar to kilopascals

We know that 1 bar is equal to 100 kpa

so  0.685*100 = 68.5 kpa

(c) 655 mm Hg to atmospheres

We know that 1 atmospheric pressure (Atm) is equal to 760 torr (mm Hg)

so 655/760 = 0.8618 atm

(d) 1.323x10⁵ Pa to atmospheres

We know that 1 atm is equal to 101,325 Pascals

so  1.323x10⁵/101,325 = 1.305 atm

(e) 2.50 atm to psi

We know that 1 atm is equal to 14.696 pound-force per square inch (psi)

so 2.50*14.696 = 36.74 psi

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west