How long would it take for a net charge of 2.5 C to pass a location in a wire if it is to carry a steady current of 5.0 mA? (b) If the wire is actually connected directly to the two electrodes of a battery and the battery does 25 J of work on the charge during this time, what is the terminal voltage of the battery?

Given Information:  

Charge = Q = 2.5 C

Current = I = 5 mA = 0.005 A

Work done = E = 25 J

Required Information:  

time = t = ?

Voltage = V = ?

time = 500 seconds

Voltage = 10 volts

Explanation:

As we know the current flowing in a circuit is given by

I = Q/t

t = Q/I

t = 2.5/0.005

t = 500 seconds

As we know the voltage is given by

V = E/Q

V = 25/2.5

V = 10 volts

this is poiselle's equation from fluid mechanic in physics. mech eng

grav potential energy