A magnetic field has a magnitude of 1.2 \times 10^{-3} T, and an electric field has a magnitude of 4.6 \times 10^{3}N/C. Both fields point in the same direction. A positive 1.8 \mu C charge moves at a speed of 3.1 \times 10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.

F = 113.4.N

Explanation: Net Force is the total forces acting in an object. In this case, there are two forces acting on the charge: one due to magnetic field (Fm) and another due to electric field (Fe). So, net force is

F = Fe + Fm

Force due to electric field

To determine this force:

Fe = q.E, where q is the charge and E is electric field.

Calculating:

Fe = q.E

Fe = 1.8..4.6.

Fe = 8.28.N

Force due to magnetic field: It can only happens when the charge is in movement, so

Fm = q.(v×B), where v represents velocity and B is magnetic field

The cross product indicates that force is perpendicular to the velocity and the field.

Calculating:

Fm = q.v.B.senθ

As θ=90°,

Fm = q.v.B

Fm =  1.8..3.1..1.2.

Fm = 6.696.N

F, Fm and Fe make a triangle. So, using Pythagorean theorem:

F =

F =

F = 113.4.N

The net force acting on the charge is F = 113.4.N

hèllo, sorry i really need some more points so if you need this qustion answered than retype it

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.