A ball is thrown into the air with an initial velocity of 10 m/s at an angle of 45 degrees above the horizontal, as represented above. If air resistance is negligible the time needed for the ball to return to the ground is most nearly:.

1.44 s

Explanation:

Since it is a projectile motion, we use the formula for the total time of flight,t

t = 2Usinθ/g where U = initial velocity of ball = 10 m/s, θ = 45 and g = 9.8 m/s²

t = 2Usinθ/g = 2 × 10sin45/9.8 = 1.44 s

So, the time needed for the ball to return to the ground is most nearly: 1.44 s

6/12=1/2

step-by-step explanation:

c. newton's third law of motion