CALC A uniform disk with radius R = 0.400 m and mass 30.0 kg rotates in a horizontal plane on a frictionless vertical axlethat passes through the center of the disk. The angle through which the disk has turned varies with time according to 6(t) =(1.10 rad/s)t + (6.30 rad/52)tz What is the resultant linear acceleration of a point on the rim of the disk at the instant whenthe disk has turned through 0.100 rev?

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

i believe the answer is electric potential.

explanation:

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015