1. a) A baseball player is stealing second base traveling at 4.0 m/s and accelerating at 2.0 m/s- for 3.0
seconds. What is the final speed at the end of the 3.0 s?

10.0 m/s

Explanation:

The motion of the player is a uniformly accelerated motion (=at constant acceleration).

Therefore, we can calculate the final speed by using the following suvat equation:

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

In this problem:

u = 4.0 m/s is the initial velocity

is the acceleration

t = 3.0 s is the time

Therefore,

So, the final speed is 10.0 m/s.

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