An archer puts a 0.285 kg arrow in a bow and uses an average force of 182 N to draw the string back 1.32 m. Assume the energy stored in the bow is transferred to the arrow when it is shot. (a) What is the speed of the arrow as it leaves the bow

speed of the arrow as it leaves is 41.05 m/sec

Explanation:

We have given mass m = 0.285 kg

Average force F = 182 N

Distance traveled d = 1.32 m

We know that work done = force distance

Sp work done =

Now according to  work energy theorem work done will be equal to kinetic energy

So

v = 41.05 m/sec

So speed of the arrow as it leaves is 41.05 m/sec

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

option number c is the right answer.