Tarik winds a small paper tube uniformly with 189 turns 189 turns of thin wire to form a solenoid. The tube's diameter is 7.99 mm 7.99 mm and its length is 2.19 cm 2.19 cm . What is the inductance, in microhenrys, of Tarik's solenoid?

102.8 μH

Explanation:

The (self) inductance of a coil based on its own geometry is given as

L = (μ₀N²A)/l

where

μ₀ = magnetic constant = (4π × 10⁻⁷) H/m

N = number of turns = 189

A = Cross sectional Area = (πD²/4) = (π×0.00799²/4) = 0.00005014 m²

l = length of the solenoid = 2.19 cm = 0.0219 m

L = (4π × 10⁻⁷ × 189² × 0.00005014)/0.0219

L = 0.0001028131 H = (1.028 × 10⁻⁴) H = (102.8 × 10⁻⁶) H = 102.8 μH

Hope this Helps!!!

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