A parallel-plate capacitor stores charge Q. The capacitor is then disconnected from its voltage source, and the space between the plates is filled with a dielectric of constant κ = 2. What is the relationship between the stored energies of the capacitor, where PEi is the initial stored energy, and PEf is the stored energy after the dielectric is inserted?
a. PEf = 2PEi
b. PEf = 0.25PEi
c. PEf = 0.5PEi
d. PEf = PEi
Answers: 1
and the stored energy after the dielectric is inserted 
is:
that is connected to a voltage source 
holds a charge of 
. Then we disconnect the voltage source and keep the charge 
constant . If we insert a dielectric of 
between the plates while we keep the charge constant, we found that the potential decreases as:
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