A 2.37-F and a 5.36-F capacitor are connected in series across a 40.0-V battery. A 8.45-F capacitor is then connected in parallel across the 2.37-F capacitor. Determine the voltage across the 8.45-F capacitor.

The voltage across the 8.45F capacitor is 27.73 Volts

Explanation:

Given that,

A  2.37-F and a 5.36-F  capacitor are connected in series across a 40.0 V battery,

To Find:

V₁  = ? (voltage across the 10.00 µF capacitor)

Solution:

For Capacitor Series Combination we have

Substituting the values we get

As Capacitors are connected in series they have the same charge on each plates, and is given by,

Substituting the values we get

Also in Series voltage will be different across C₁ and C₂,

Therefore voltage across C₁  will be

Substituting the values we get

Now according to the given condition,

8.45F capacitor is then connected in parallel across the 2.37 F capacitor,

Therefore we know in Parallel, Voltage remain Same, Hence Voltage across 8.45F capacitor will be same as that of voltage across V₁.

Hence,

The voltage across the 8.45F capacitor is 27.73 Volts

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

conduction, convection, radiation