An airplane pilot wishes to fly due west. A wind of 80.0 km/h (about 50 mi/h) is blowing toward the south. (a) If the airspeed of the plane (its speed in still air) is 320.0 km/h (about 200 mi/h), in which direction should the pilot head?

14.48° North of West.

Explanation:

The conditions mentioned in the question has been drawn in the figure below where,

As ΔABC is a right angle triangle, for calculating the direction of airplane so that it can travel to west, we need to calculate the direction of vector CA which can be calculated with the help of sine theta.

So,

θ

Thus the value of θ = 14.48°

So, the pilot should head towards 14.48° North of West.

the right answer is 0.3 meters per second

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation