A bobsled team pushes a 132-kilogram bobsled. If the combined push of the team is 450.0 Newtons and the bobsled also experiences a force of friction of 35 Newtons, what is the acceleration of the bobsled? A. The bobsled's acceleration is 3.14 m/s2 . B. The bobsled's acceleration is 3.18 m/s2 . C. The bobsled's acceleration is 3.6 m/s2 . D. The bobsled's acceleration is 9.08 m/s2 .

A. The bobsled acceleration is 3.14 m/s²

Explanation:

Given:

Mass of the bobsled (m) = 132 kg

Force of push (F) = 450.0 N

Force of friction (f) = 35 N

Let the acceleration of the bobsled be 'a' m/s².

Now, as per Newton's second law, the net force acting on a body is equal to the product of mass and acceleration.

Net force acting on the bobsled is equal to the difference of applied force and friction and is given as:

Now, from Newton's second law,

Plug in all the values given and solve for 'a'. This gives,

Therefore, the acceleration is 3.14 m/s². So, option (A) is correct.

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