A circuit consists of a 9.3-mH coil, a 16.0-V battery, a parallel combination of a 19-Ω resistor and a 6.0-Ω resistor, and a switch, all in series. What is the time constant of this circuit?

τ = 0.00203 seconds

Explanation:

The time constant τ in a R-L circuit is given by

τ = L/R

First we have to find out the equivalent resistance of the circuit.

Since there is a parallel combination of 19 Ω and 6.0 Ω resistor

Req = 19*6/19+6

Req = 4.56 Ω

Now we can find out the time constant

τ = L/R

τ = 0.0093/4.56

τ = 0.00203 seconds

Therefore, the time constant of this circuit is 0.00203 seconds.

divide the right side by the left side

0.024÷1.2=0.02 for example

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