What is the maximum torque on a 400-turn circular coil of radius 0.65 cm that carries a current of 1.2 mA and resides in a uniform magnetic field of 0.2 T? Answer in units of N · m.

Torque,

Explanation:

Given that,

Number of turns in a circular coil, N = 400

Radius of the circular coil, r = 0.65 cm

Current in the coil, I = 1.2 mA

Uniform magnetic field in the circular coil, B = 0.2 T

Torque in the circular coil is given by :

For maximum torque,

So, the net torque about the vertical axis is . Hence, this is the required solution.

the body's situation won't change the forces are equal opposit and on the same body

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft