At a waterpark, sleds with riders are sent along a slip-pery, horizontal surface by the release of a large compressed spring. The spring, with force constant k = 40.0 N/cm and negli-gible mass, rests on the frictionless horizontal surface. One end is in contact with a stationary wall. A sled and rider with total mass 70.0 kg arc pushed against the other end, compressing the spring 0.375 m. The sled is then released with zero initial velocity. What is the sled's speed when the spring (a) returns to its uncompressed length and (b) is still compressed 0.200 m?

a) 2.8m/s

b) 2.4m/s

Explanation:

Given:

K= 40N/cm, convert to N/m we have: k= 4000N/m

m=70kg

x=0.375

For (a)

We find the energy stored in the spring with the expression:

;

U = 281 N.m

To find the sled speed, let's use the work energy theorem which is:

Therefore

V= 2.8m/s

b) We need to calculate energy stored at 0.200m.

Let's use:

;

U = 201N.m

We now use energy theorem:

We now have

V = 2.4m/s

answer: i think he can see forward ten seconds and move forward ten seconds but giorno can undo his actions with ger.

explanation:

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.