A small but heavy lead weight is attached to a lightweight string with a length of 0.55 m. Determine the natural period of the lead weight if it oscillates with a small amplitude on the end of the string.

The natural period is 1.49 s

Explanation:

T = 2πsqrt(L/g)

T is the natural period

π = 3.142

L is length of the string = 0.55 m

g is acceleration due to gravity = 9.8 m/s^2

T = 2×3.142sqrt(0.55/9.8) = 6.284sqrt(0.05612) = 6.284×0.237 = 1.49 s

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg