Light strikes a metal surface, causing photoelectric emission. The stopping potential for the ejected electrons is 7.9 V, and the work function of the metal is 3.3 eV. What is the wavelength of the incident light

The wavelength of light is .

Explanation:

Given:

Work function of the metal (Ф) = 3.3 eV =

Stopping potential (V) = 7.9 V

Wavelength of light (λ) = ?

We know that for photoelectric effect to take place, the minimum energy of  the incident photon must be equal to the sum of maximum kinetic energy and the work function of the metal surface. This means,

Now, the kinetic energy of the electrons emitted must be at least equal to the product of stopping potential and the charge on electron of the metal in order to escape the metal surface. Therefore,

Where, 'e' is the charge on one electron =

Also, the energy of photon is expressed as:

Now, the above equation becomes,

Plug in all the given values and solve for λ. This gives,

Therefore, the wavelength of light is .

wavelength variability is the right one