A proton moves straight upward (away fromthe ground) through a uniform magnetic fieldthat points from east to west and has a mag-nitude of 5.9 T. If the proton moves with a speed 3.6×107m/s through this field, what is the magnitudeof the force acting on it? The charge on aproton is 1.60×10−19.Answer in units of N

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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