A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the drill’s angular acceleration. Answer in units of rad/s 2

Angular acceleration, is

Explanation:

Given that,

Initial speed of the drill,

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed,

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

So, the drill's angular acceleration is .

are there answer choices to this question? this seems like a question where you have options to choose from.