A 4.0-μF capacitor that is initially uncharged is connected in series with a 4.0-kΩ resistor and an ideal 17.0-V battery. How much energy is stored in the capacitor 17 ms after the battery has been connected?

2.473x10^-4J

Explanation:

C=(4x10^-6)farads, R=4000omhs, Vinital=17v, t=.017s

Use these equations τ=RC, Vfinial=Vinital(1-e^(-t/τ)), and En=

τ=(4x10^-6)(4000)=.016

Vfinial=17(1-e^(-.017/.016))=11.12v

En==2.473x10^-4J

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!

it doesn't. it was imagined up in the middle ages.