A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material that fills the volume between the plates has a dielectric constant of 4.00. The plates of the capacitor are connected to a 400 V battery.

Part A

What is the capacitance of the capacitor?

C = F

Part B

What is the charge on either plate?

Q = C

Part C

How much energy is stored in the charged capacitor?

U = J

a) , b) , c)

Explanation:

a) The capacitance of two parallel plates capacitor with dielectric is given by the following expression:

Where:

- Dielectric constant.

- Vaccum permitivity.

- Plate area.

- Distance between plates.

Hence, the capacitance of the system is:

b) The charge can be found by using the definition of capacitance:

c) The energy stored in the charged capacitor is:

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2