As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m × 2.0 m has a charge of 8.0 × 10-11 C distributed uniformly throughout its volume. Use Gauss's law to determine the electric field at
point , which is located within the slab beneath its center, 1.0 mm from one of the faces.

cancer risk hope this

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j