A swimming pool is circular with a 30-ft diameter. The depth is constant along east-west lines and increases linearly from 5 ft at the south end to 10 ft at the north end. Find the volume of water in the pool. (Round the answer to the nearest whole number.)

Answer : The volume of water in the pool is, 2473 ft³

Explanation :

First we have to calculate the average depth.

Given:

Diameter = 30 ft

Depth range : 1 to 6 ft linearly

average depth =

Now we have to calculate the volume of water in the pool.

Volume = area × average depth

V = π × (radius)² × 3.5

V = π × (30/2)² × 3.5

V = π × (15)² × 3.5

V = π × 225 × 3.5

V = 3.14 × 225 × 3.5

V = 2472.75 ft³ ≈ 2473 ft³

Therefore, the volume of water in the pool is, 2473 ft³

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day