Given the indices of refraction n_1 and n_2 of material 1 and material 2, respectively, rank these scenarios on the basis of the phase shift in the refracted ray.

1) Rank from largest to smallest. To rank items as equivalent, overlap them.

a) n1,water=1.33
n2,air=1.00

b) n1,water=1.33
n2,quartz=1.46
c) n1,water=1.33
n2,diamond=2.42
d) n1,air=1.00
n2,quartz=1.46
e) n1,benzene=1.50
n2,water=1.33
f) n1,air=1.00
n2,water=1.33
2) Rank these scenarios on the basis of the phase shift in the reflected ray.
a) n1,benzene=1.50
n2,water=1.33
b) n1,air=1.00
n2,quartz=1.46
c) n1,water=1.33
n2,quartz=1.46
d) n1,water=1.33
n2,air=1.00
e) n1,water=1.33
n2,diamond=2.42
f) n1,air=1.00
n2,water=1.33

a)  order of refraction is a, e, de, c , c) a f g

Explanation:

a) when lightning is refracted it must comply with the law of refraction

          .n₁ sin θ₁ = n₂ sinθ₂

          sin θ / sin δδa) when lightning is refracted it must comply with the law of refraction

          .n1 sin θ₁ = n2 sin θ ₂

          Sint θ1 / sin θ2 = n2 / n1

1 we see that the ray deviation is promotional to the ratio of the refractive indices

The order of refraction is a, e, de, c

.b) When a ray passes from a medium with less indicated refraction to a higher index the part of the reflected ray has a phase change of 180º

a) no phase change

b) reflected ray has a phase change of 180º

c) no phase change

d) no phase change

e) there is a phase change

f) these phase changeo  

1 we see that the ray deviation is promotional to the ratio of the refractive indices

The order of refraction is a, e, de, c

.b) When a ray passes from a medium with less indicated refraction to a higher index the part of the reflected ray has a phase change of 180º

a) no phase change

b) reflected ray has a phase change of 180º

c) no phase change

d) no phase change

e) there is a phase change

f) ay phase vabio

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day