A double-slit interference experiment is performed in the air. Later, the same apparatus is immersed in benzene (which has an index of refraction of 1.50), and the experiment is repeated. When the apparatus is in benzene, you observe that the interference fringes are

A - more widely spaced than when the apparatus is in air.

B- more closely spaced than when the apparatus is in air.

C- equally spaced as when the apparatus is in air.

The correct option is B

Explanation:

Double slit interference occurs as a result of the diffraction of light when passing through the narrow slit aperture.

The pacing between two consecutive interference fringes in a double-slit interference is given by;

y = λD/d

where λ is the wavelength of the light

D is the distance between the light source and the viewing screen

d is the slit spacing

When the experiment is performed in air and in benzene, bothe D and d are constant. The parameter that is varied is the index of refraction of the medium which are the air and the benzene and its given by

n = λvacuum/λ

the answer is d. 4

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50 inches should be the resultant vector