The relative angle at the knee changes from 0 to 85 degrees during the knee flexion phase of a squat exercise. If 10 complete squats are performed, what is the total angular distance undergone at the knee (in degrees)?

the total angular distance undergone at the knee is 1700°

Explanation:

You know that in a knee flexion, the angle goes from 0° to 85.

Now, in one squat, the knee flex and the angle goes from 0° to 85° (85° of angular distance) and when the knee straigthens, the angle goes from 85° to 0° (another 85° of angular distance)

So in one squat, the total angular distance undergone at the knee is d = 85° + 85° = 170°

and if in one squat, the angular distance is 170°, in ten, the angular distance will be ten times that number:

d = 10*170° = 1700°

i don't know that i agree with that but what's the question ?