A 9.29 kg particle with velocity is at x = 7.86 m, y = 9.84 m. It is pulled by a 9.78 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?

Explanation:

The question didn't state the velocity in terms of i and j but let take it as

a. To find particle's angular momentum:

       where r= x+y  

b.To find torque:

c.

The Newton's 2nd law of motion said that the rate change of momentum is equal to the net torque,

so Δl/Δt = (+96.24k)Nm