Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.085 V. How much work is done by the electric force when a sodium ion (charge

The work that has been done by the electric force is 1.36 x 10⁻²⁰ J

Explanation:

given information:

electric potential, V = 0.085 V

we can use the following formula to calculate the electric force of sodium

W = - eΔV

where

W = work (joule, J)

e = charge (coulomb, C)

V = electric potential (volt, V)

The charge of sodium ion is 1.6 x 10⁻¹⁹. Therefore,

W = - eΔV

   = - (1.6 x 10⁻19 C) (-0.085)

   = 1.36 x 10⁻²⁰ J

d is the correct answer